z^2+4z+4-i=0

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Solution for z^2+4z+4-i=0 equation:


Simplifying
z2 + 4z + 4 + -1i = 0

Reorder the terms:
4 + -1i + 4z + z2 = 0

Solving
4 + -1i + 4z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -1i + 4z + -4 + z2 = 0 + -4

Reorder the terms:
4 + -4 + -1i + 4z + z2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1i + 4z + z2 = 0 + -4
-1i + 4z + z2 = 0 + -4

Combine like terms: 0 + -4 = -4
-1i + 4z + z2 = -4

Add '-4z' to each side of the equation.
-1i + 4z + -4z + z2 = -4 + -4z

Combine like terms: 4z + -4z = 0
-1i + 0 + z2 = -4 + -4z
-1i + z2 = -4 + -4z

Add '-1z2' to each side of the equation.
-1i + z2 + -1z2 = -4 + -4z + -1z2

Combine like terms: z2 + -1z2 = 0
-1i + 0 = -4 + -4z + -1z2
-1i = -4 + -4z + -1z2

Divide each side by '-1'.
i = 4 + 4z + z2

Simplifying
i = 4 + 4z + z2

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